Leetcode 890. Find and Replace Pattern Sure, let’s break down the solution for the LeetCode problem “890. Find and Replace Pattern”. Here we will discuss the problem statement, potential clarifications, a detailed strategy, code implementation in C++, and analysis of the time complexity.
You are given a list of strings words and a string pattern. You need to return a list of words that match the given pattern.
A word matches the pattern if there exists a permutation of letters such that pattern could be transformed into the word. Match the pattern means that there is a bijection between a letter in pattern and a letter in word.
words list and the pattern have the same length?
To solve the problem, you need to compare the structure of each word with the pattern. This can be achieved using a mapping mechanism to ensure each character in the word maps to a character in the pattern uniquely and vice versa.
Here’s a step-by-step strategy:
Here is the C++ implementation of the strategy outlined:
#include <vector>
#include <string>
#include <unordered_map>
using namespace std;
vector<int> normalize(const string& s) {
unordered_map<char, int> char_to_index;
vector<int> normalized;
for (char c : s) {
if (char_to_index.find(c) == char_to_index.end()) {
char_to_index[c] = char_to_index.size();
}
normalized.push_back(char_to_index[c]);
}
return normalized;
}
vector<string> findAndReplacePattern(vector<string>& words, string pattern) {
vector<string> result;
vector<int> pattern_norm = normalize(pattern);
for (const string& word : words) {
if (normalize(word) == pattern_norm) {
result.push_back(word);
}
}
return result;
}
This approach ensures a clear, concise, and efficient solution to identify and select words matching the given pattern in terms of structural character mapping.
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