Given two integers, a
and b
, determine the number of bit changes (i.e., bit flips) required to convert a
into b
. Essentially, you need to find the number of differing bits between the binary representations of a
and b
.
a
and b
?
a
and b
. This will highlight the differing bits:
a
and b
.def bit_change_count(a: int, b: int) -> int:
# Perform XOR operation between a and b
xor_result = a ^ b
# Count the number of set bits
count = 0
while xor_result:
count += xor_result & 1 # Increment if the least significant bit is 1
xor_result >>= 1 # Right shift the bits to check next bit
return count
O(n)
, where n
is the number of bits in the maximum of a
or b
. Here, each shift operation and bit count step is constant, but this has to be done for each bit.O(1)
, as we are using a constant amount of space regardless of the input size.This algorithm efficiently computes the number of differing bits by leveraging bitwise operations and simple counts. It operates in linear time relative to the number of bits, which is optimal for this type of problem.
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