Leetcode 3178. Find the Child Who Has the Ball After K Seconds Sure! Let’s dive into solving a LeetCode problem. Below are sections detailing the problem statement, clarifying questions, strategy, code implementation, and analysis of time complexity.
Given n
children standing in a line, numbered from 0
to n-1
, and a ball initially given to the child at position start
. After every K
seconds, the ball is passed to the next child. If the ball is at position i
and it’s the end of the line (the ball should be passed to child n-1
), it returns to the start of the line (child 0
). You need to determine which child has the ball after t
seconds.
Is K
always less than n
?
This would facilitate direct modulo calculations.
Is it guaranteed that n
and start
are non-negative integers and t
is a non-negative integer?
Can K
be zero?
This would imply that the ball is passed to the next child instantly, essentially acting as a rotating array within certain boundaries.
With the provided details, the problem boils down to calculating the position after t
seconds of iterating through the children. Considering that after reaching the end of the line the ball returns to the start, the problem can be significantly simplified using modulo arithmetic.
t * K
since every second counts for exactly K
moves.n
on the calculated movements to wrap around the children line.start
.n
again to ensure it fits within the bounds [0, n-1].Here is how the solution can be implemented in Java:
public class Solution {
public int findChildWithBall(int n, int start, int K, int t) {
// Total moves after t seconds
int totalMoves = t * K;
// Calculate the final position using modulo arithmetic
int finalPosition = (start + totalMoves) % n;
return finalPosition;
}
}
Time Complexity: O(1) The solution involves basic arithmetic operations, which are constant time operations.
Space Complexity: O(1) No extra space is used beyond the input parameters and a few local variables.
This solution utilizes straightforward mathematical operations to calculate the final position of the ball, leveraging the modulo operator to handle the cyclic nature of the problem efficiently.
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