You are given an integer array arr
. You need to find the permutation of the array arr
that has the minimum sum of absolute differences between consecutive elements. More specifically, you need to reorder the elements in arr
such that the total sum of absolute differences between each consecutive pair of elements is minimized. Return the permutation that achieves this smallest sum.
Given the problem requires a permutation with a minimal sum of absolute differences, a natural strategy is to order the elements in some optimal configuration. Here is a structured approach to tackle this problem:
If we sort the array in ascending order, the sum of absolute differences between consecutive elements will naturally be minimized. This is because, for any two elements ( a_i ) and ( a_{i+1} ) in a sorted array, ( | a_{i+1} - a_i | ) is minimized. Consecutive differences in sorted arrays tend to be the smallest possible within the given array. |
Thus, the overall time complexity is ( O(n \log n) ).
Let’s implement this approach in code:
def min_cost_permutation(arr):
# Sorting the input array
arr_sorted = sorted(arr)
# Returning the sorted array as it is the required permutation
return arr_sorted
# Example usage
arr = [4, 2, 1, 3]
print(min_cost_permutation(arr)) # Output: [1, 2, 3, 4]
Feel free to ask more specific questions or for further elaboration on any part of the solution!
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