Given a string s
, the task is to remove duplicate characters from s
such that each character appears only once. The output should be the minimized length of the string after removing the duplicates.
To solve this problem, we can use a set data structure which inherently maintains unique elements. The basic approach can be broken down into these steps:
s
and add it to the set.len(set)
) will represent the number of unique characters, which is the answer.The use of a set ensures that each character only appears once, automatically handling the removal of duplicates.
def minimize_string_length(s: str) -> int:
# Initialize a set to track unique characters
unique_chars = set()
# Add each character in the input string to the set
for char in s:
unique_chars.add(char)
# The size of the set is the number of unique characters
return len(unique_chars)
# Example usage:
print(minimize_string_length("abca")) # Output: 3
print(minimize_string_length("abcabc")) # Output: 3
print(minimize_string_length("")) # Output: 0
print(minimize_string_length("aAaA")) # Output: 2 (since 'a' and 'A' are different)
The time complexity of this solution is O(n), where n
is the length of the input string s
. This is because we iterate through each character in the string once, and each set insertion operation is average O(1) time complexity.
The space complexity is also O(n) in the worst case, where all characters in the string are unique, and hence, the set will store n
characters.
Got blindsided by a question you didn’t expect?
Spend too much time studying?
Or simply don’t have the time to go over all 3000 questions?