algoadvance

You are given a digit string num. You need to determine if the count of each digit in the string matches its value. Specifically, for each digit at index i in the string, the count of digit i in the entire string should match the digit’s value at that index. Return ‘True’ if the string satisfies this condition, otherwise return ‘False’.

Clarifying Questions:

  1. What is the range of the length of the string num?
    • The length of the string can be up to 10.
  2. Can the string contain any non-digit characters?
    • No, the string contains only digits from ‘0’ to ‘9’.
  3. Should the function be case-sensitive?
    • Since the string contains only digits, case sensitivity is not relevant.

Code:

def digit_count(num: str) -> bool:
    # Create a dictionary to hold the count of each digit
    from collections import Counter
    digit_counts = Counter(num)
    
    # Traverse through each digit
    for i in range(len(num)):
        # Check if the count of the digit i (converted to string) matches num[i] (converted to int)
        if digit_counts[str(i)] != int(num[i]):
            return False
    
    return True

# Example tests
print(digit_count("1210"))  # True
print(digit_count("030"))   # False

Strategy:

  1. Use a Counter: Utilize the Counter from the collections module to count the instances of each character (digit) in the string num.
  2. Iterate through String: Loop through each index i of the string num.
  3. Compare Counts: For each index i, check if the count of the digit str(i) in the Counter equals the integer value of num[i].
  4. Return Result: If all checks pass, return True. If any check fails, return False.

Time Complexity:

The provided solution is efficient and well within the acceptable limits for the problem constraints.

Try our interview co-pilot at AlgoAdvance.com