You are given a digit string num. You need to determine if the count of each digit in the string matches its value. Specifically, for each digit at index i in the string, the count of digit i in the entire string should match the digit’s value at that index. Return ‘True’ if the string satisfies this condition, otherwise return ‘False’.
num?
def digit_count(num: str) -> bool:
# Create a dictionary to hold the count of each digit
from collections import Counter
digit_counts = Counter(num)
# Traverse through each digit
for i in range(len(num)):
# Check if the count of the digit i (converted to string) matches num[i] (converted to int)
if digit_counts[str(i)] != int(num[i]):
return False
return True
# Example tests
print(digit_count("1210")) # True
print(digit_count("030")) # False
Counter from the collections module to count the instances of each character (digit) in the string num.i of the string num.i, check if the count of the digit str(i) in the Counter equals the integer value of num[i].True. If any check fails, return False.num, to count the frequency of each digit.num.The provided solution is efficient and well within the acceptable limits for the problem constraints.
Got blindsided by a question you didn’t expect?
Spend too much time studying?
Or simply don’t have the time to go over all 3000 questions?