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Clarifying Questions

  1. Input format: What is the format of the input? Is it guaranteed to be a non-empty string?
  2. Digit extraction: Should we consider only numeric digits (0-9) and ignore any other characters?
  3. Duplicates: How should we treat duplicate digits? For example, if the largest digit appears multiple times, should we recognize it only once?
  4. Edge cases: What if there is no second largest digit? Should we return a specific value like -1 in that case?

Assuming we have clear answers to the questions as follows:

  1. The input is a non-empty string.
  2. Only numeric digits need to be considered.
  3. Duplicates should be handled such that each digit is considered only once.
  4. Return -1 if there is no second largest digit.

Let’s proceed with the solution.

Strategy

  1. Extract digits: Traverse through the string, and collect all numeric digits.
  2. Unique digits: Store the digits in a set to maintain uniqueness.
  3. Find largest and second largest: Convert the set to a sorted list and identify the largest and second largest digits.
  4. Edge cases: Handle cases where there are fewer than two unique digits.

Code Implementation

Here’s the step-by-step implementation in Python:

def second_largest_digit(s: str) -> int:
    digits = set()

    # Extracting all unique digits
    for char in s:
        if char.isdigit():
            digits.add(int(char))

    # Convert set to a sorted list in descending order
    sorted_digits = sorted(digits, reverse=True)

    # If there are at least two unique digits, return the second largest
    if len(sorted_digits) >= 2:
        return sorted_digits[1]
    
    # If there is no second largest digit, return -1
    return -1

Time Complexity

Summary

This solution efficiently finds the second largest digit in a string by leveraging set operations for uniqueness and sorting for identifying the largest and second largest elements. This ensures that our solution remains efficient even for larger input sizes.

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