Leetcode 1374. Generate a String With Characters That Have Odd Counts Certainly! Let’s break this down into manageable sections.
LeetCode Problem 1374: Generate a String With Characters That Have Odd Counts
Given an integer n
, return a string with n
characters such that each character in the string occurs an odd number of times.
n
? Is n
always a positive integer?
n
is a positive integer and typically falls within a reasonable range for standard string operations in Java.Given n
, our goal is to return a string where each character appears an odd number of times. Let’s outline how we can achieve this:
n
is odd, we can simply repeat the same character n
times.n
is even, we can repeat one character n-1
times (which is odd) and another character 1 time (which is also odd). This way, the counts remain odd.Both these approaches ensure that each character in the string appears an odd number of times.
Here’s the implementation in Java:
public class Solution {
public String generateTheString(int n) {
StringBuilder result = new StringBuilder();
if (n % 2 == 1) {
// If n is odd, return a string with 'a' repeated n times
for (int i = 0; i < n; i++) {
result.append('a');
}
} else {
// If n is even, return a string with 'a' repeated (n-1) times and 'b' repeated 1 time
for (int i = 0; i < n - 1; i++) {
result.append('a');
}
result.append('b'); // Adding one more character to make it even-sized
}
return result.toString();
}
}
The time complexity of this solution is O(n):
n
characters to the StringBuilder
, which takes linear time relative to the number of characters.By following this approach, we ensure that the string generated meets the criteria of having each character appear an odd number of times.
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