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Leetcode 1317. Convert Integer to the Sum of Two No

Problem Statement

LeetCode Problem 1317: Convert Integer to the Sum of Two No-Zero Integers

Given an integer n, return an array ans of length 2, where:

Clarifying Questions

  1. Q: Can n be negative?
    • A: No, based on the problem constraints, n is a positive integer (1 <= n <= 10^4).
  2. Q: Do we have to return the smallest possible integers?
    • A: No specific requirement to return the smallest possible integers, just that both integers should not contain any zero digits.
  3. Q: Can the solution have multiple possible answers?
    • A: Yes, as long as the two integers do not contain any zero digits, any valid answer will be accepted.

Strategy

To solve this problem:

  1. Iterate through possible values for a starting from 1 to n-1.
  2. For each a, calculate b as n - a.
  3. Check if both a and b do not contain the digit ‘0’.
  4. If a and b both do not contain ‘0’, return the pair [a, b].

Helper Function

We will need a helper function hasZero(int num) that checks if a given integer contains the digit ‘0’.

Time Complexity

The time complexity is O(n * k), where n is the given integer, and k is the maximum number of digits in n (which is negligible compared to n).

Code

public class Solution {
    public int[] getNoZeroIntegers(int n) {
        for (int a = 1; a < n; a++) {
            int b = n - a;
            if (!hasZero(a) && !hasZero(b)) {
                return new int[]{a, b};
            }
        }
        // The problem guarantees a solution, so we should never reach here.
        return new int[]{-1, -1};
    }

    private boolean hasZero(int num) {
        while (num > 0) {
            if (num % 10 == 0) {
                return true;
            }
            num /= 10;
        }
        return false;
    }

    public static void main(String[] args) {
        Solution sol = new Solution();
        int n = 1010;
        int[] result = sol.getNoZeroIntegers(n);
        System.out.println("Result: [" + result[0] + ", " + result[1] + "]");
    }
}

Explanation

  1. Iteration: We iterate through possible values for a from 1 to n-1.
  2. Complement Calculation: For each a, we calculate b as n - a.
  3. Zero Check: The helper function hasZero checks if any number contains the digit zero.
  4. Return Valid Pair: If both a and b pass the check, we return the pair [a, b].

This approach ensures that we find the required no-zero integers efficiently.

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